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愛知県高校入試 2020 難易度 10

&=&21\\ &=&\sqrt{72}\\ & & & \\ \hline PV &=&81-18\\ \(\begin{eqnarray}\displaystyle \mathrm{OH}&=&\color{blue}{3\sqrt{7}}\,\,0\,) \(\,x\,\)\(\,\mathrm{C}\,\), \(\,x\,\)\(\,y=0\,\) \(\,\mathrm{AGH=90^{\circ}}\,\), , (2) \(\,\mathrm{S}\,\), \(\,\mathrm{B\,\rightarrow \,A}\,\) \displaystyle =\frac{10(2x-3)-3(3x-10)}{15}\\ &=&\color{blue}{20^{\circ}}+\color{magenta}{72^{\circ}}\\ &=&63\\ \(\begin{eqnarray}\displaystyle \(\hspace{4pt}\mathrm{C}\,\underline{(\,8\,,\,0\,)}\), \(\,\mathrm{C}\,\) &=&\underline{\frac{1\pm \sqrt{13}}{2}} \displaystyle =\underline{\frac{11x}{15}}=\underline{\frac{11}{15}\,x}\), \((\,45\,,\,12\,)\) & & & 1 \\ \hline \(\,\mathrm{2}\,\), \(\,\mathrm{Q}\,\)\(\,\mathrm{AB}\,\) \(\,\mathrm{AB=6}\,\)\(\,\mathrm{O}\,\)\(\,\mathrm{ABCD}\,\), \(\,\mathrm{ABCD}\,\)\(\,\mathrm{H}\,\) \(\,(\color{blue}{})+(\color{blue}{1})=(\color{blue}{-1})+(\color{blue}{2})\,\) \(\,x\,\)\(\,y\,\) \(\,\mathrm{EC=2BE}\,\) \(\hspace{4pt}\displaystyle \frac{36}{60}=\frac{3}{5}(\,\mathrm{km}/\,)\) &=&\underline{92^{\circ}} \end{eqnarray}\), V&=&\frac{1}{3}\times \color{red}{6}^2\times \color{blue}{3\sqrt{7}}\\ \(\,2600\,\), \(\,400\,\)\(\,1200\,\) \(\,\mathrm{B}\,\) \end{eqnarray}\) \(\,1\,\)\(\,3\,\)\(\,5\,\), \(\,\mathrm{O-ABC}\,\) \(\,2\,\)\(\,\mathrm{A,B}\,\) \(\,3\,\)\(\,\mathrm{E,F,G}\,\) The following two tabs change content below. &=&\frac{1}{2}\times 36\sqrt{7}\\ , \end{eqnarray}\), \(\hspace{10pt}5x(x-2)-(2x+3)(2x-3)\\ \(\,\mathrm{AH}\,\) & & & 3 \\ \hline All rights reserved. \end{eqnarray}\) \mathrm{AF^2}&=&\mathrm{AD^2+DF^2}\\ \(\,\mathrm{OABC}\,\)\(\,V_1\,\) &=&\color{blue}{6\sqrt{2}} 100 , , (), , (;), , 3731, 1, 20, , , , , , , , ((+_+)). \(\,x=4\,\)\(\,y=48\,\) x&=&\underline{50()} &=&\frac{3\sqrt{7}}{\sqrt{2}}\\ , (1) &=&\color{red}{2}:\color{red}{6} \end{eqnarray}\), & & & 0 \\ \hline \(\begin{eqnarray} 24WebWeb, IP042-679-6610. \(\,\mathrm{O}\,\)\(\,\mathrm{C}\,\) &=&\color{magenta}{37} 2020(2a TOP, TOP. \end{eqnarray}\), \(\,\mathrm{GBE}\,\)\(\,\mathrm{GHA}\,\) \((\,65\,,\,0\,)\) \(\,2\,\) \(\,9\,\), \(\,2\,\) &=&9^2-(3\sqrt{2})^2\\ \(\hspace{4pt}\displaystyle y=-\frac{3}{5}\,x+39\), \(\,x\,\) =\color{red}{\sqrt{5}}(\color{blue}{\sqrt{2}+1})\color{red}{\sqrt{3}}(\color{blue}{\sqrt{2}-1})\\ =3.2\), \(\displaystyle \color{red}{\frac{16}{3}}\) \(\,2\,\), \(\,y=3x^2\,\) \(\hspace{4pt}\displaystyle \frac{48}{60}=\frac{4}{5}(\,\mathrm{km}/\,)\) \(\,2\,\)\(\,1\,\)\(\,1\,\)\(\,11\,\) \(\,\mathrm{OH=3\sqrt{7}}\,\) PDFAdobeReader \(ax^2+bx+c=0\) & & & 3 \\ \hline , \(\,300\,\)\(\,2600\,\) & & & 2 \\ \hline , \(\,\mathrm{S}\,\)\(\,\mathrm{B}\,\)\(\,\mathrm{C}\,\) 1 \end{eqnarray}\) \end{eqnarray}\), 2 \(\,20\,\)\(\,21\,\) , \(\,4\,\)\(\,3\,\)\(\,2\,\)\(\,19\,\) . & & & 4 \\ \hline \(\hspace{10pt}\displaystyle \frac{45+36+30+12+5+0}{40}\\ h&=&\frac{9\sqrt{7}}{3\sqrt{2}}\\ \(\hspace{10pt}\displaystyle \color{red}{x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}\) =3+8\\ \end{array}\), & & & 5 \\ \hline \(\,20\,\)\(\,21\,\)\(\,3\,\)\(\,10\,\), &=&\sqrt{(3\sqrt{7})^2+3^2}\\ \(\begin{eqnarray} \(\,\mathrm{A}\,\)\(\,\mathrm{OBC}\,\) \end{eqnarray}\), (7) \mathrm{\color{red}{QR}}&=&\sqrt{21}(\,\,0\,) \(\,\mathrm{AP}\,\)\(\,\mathrm{R}\,\) \mathrm{DEC}&=&\mathrm{DBE+BDE}\\ , \(\,\mathrm{COA=40^{\circ}}\,\) & & & 4 \\ \hline \end{eqnarray}\) . , \(\,\mathrm{A}\,\)\(\,5\,\) \(\,\mathrm{B}\,\)\(\,\mathrm{A}\,\)\(\,\mathrm{36\,km}\,\) \(\,\mathrm{AF}\,\)\(\,\mathrm{EF}\,\) \(\,\mathrm{ABM}\,\)\(\,\color{magenta}{S_1}\,\) \(\,\mathrm{A}\,\)\(\,\mathrm{C}\,\)\(\,\mathrm{8\,km}\,\) \(\,2\,\) \color{blue}{h}&=&\frac{18\sqrt{7}}{6\sqrt{2}}\\ 5^2&=&2^2+\mathrm{QR^2}\\ \(\,\mathrm{AE}\,\)\(\,\mathrm{GF}\,\) \(\,\mathrm{\color{blue}{B-C}}\,\)\(\hspace{4pt}\displaystyle y=\frac{1}{5}\,x-1\), \(\hspace{4pt}\mathrm{C}\,(\,t\,,\,0\,)\) \(\,45\,\), \(\,\mathrm{FDH}\,\)\(\,\mathrm{FCB}\,\) \(\,\mathrm{AGF=EGF=90^{\circ}}\,\) , \(\,\mathrm{A}\,\)\(\,\mathrm{8\,km}\,\)\(\,\mathrm{C}\,\)\(\,40\,\) pdf / J-G-2020-20200290000. , \mathrm{QR^2}&=&5^2-2^2\\ x^2-x-3&=&0 \(\begin{eqnarray} \(\,0\,\)\(\,1\,\) \(\begin{eqnarray}\displaystyle \(\begin{eqnarray}\displaystyle \displaystyle =\frac{76}{40}\\ , \(\begin{eqnarray}\displaystyle line! =\underline{(x-1)(x-9)}\), - 20201111; - 20201110; 12 - 2020119; . 2 (adsbygoogle = window.adsbygoogle || []).push({}). \end{eqnarray}\), 2018350PV \(\begin{eqnarray}\displaystyle , . \(\hspace{4pt}\displaystyle \frac{12}{60}=\frac{1}{5}(\mathrm{km/})\) \(\,\mathrm{HDF}\,\)\(\,\mathrm{HGA}\,\) , \(\,\mathrm{AG}\,\)\(\,\mathrm{GE}\,\), \(\,\mathrm{ABCD}\,\) \(\,\mathrm{FC=3DF}\,\) \(\,\mathrm{AOB=ABC}\,\) \(\,\mathrm{L,M,N}\,\) \(\,\mathrm{A}\,\)\(\,1,3,5\,\)\(\,3\,\) \(\begin{eqnarray}\displaystyle \(\,\underline{-4}\,\) \(\,\mathrm{AB}\,\) \(\,\mathrm{DBE=36^{\circ}}\,\) \(\,2\,\), \(\,\mathrm{EGF}\,\) \(\,\mathrm{OBC}\,\)\(\,\mathrm{ABCD}\,\)\(\,\mathrm{OBC}\,\) \(\,\mathrm{A}\,\)\(\,\mathrm{OBC}\,\)\(\,\color{blue}{h}\,\) \(\,20\,\) , \(\,\mathrm{CBD=\color{red}{36^{\circ}}}\,\) =5x^2-10x-4x^2+9\\ \(\,\mathrm{COD=\color{magenta}{72^{\circ}}}\,\) \(\,x\,\) , \(\,2020\,\)\(\,\mathrm{A}\,\), &=&\underline{36\sqrt{7}(\,\mathrm{cm^3}\,)} , . 4x&=&200\\ \displaystyle =\frac{20x-30-9x+30}{15}\\ \end{eqnarray}\), 2020359 \(\hspace{10pt}\displaystyle y=-\frac{8}{3}\,x+\color{red}{\frac{16}{3}}\) \(\,\mathrm{A\,(\,1\,,\,2\,)}\,\) , \(\,\mathrm{A-C-B}\,\)\(\,\mathrm{12\,km}\,\) \mathrm{OI}&=&\sqrt{81-9}\\ Takuji Kunitate & & & 3 \\ \hline =5x^2-10x-(4x^2-9)\\ &=&\sqrt{72}\\ \(\begin{eqnarray} \(\begin{eqnarray}\displaystyle , \(\,\pi\,r^2\,\) \end{eqnarray}\), \(\,\mathrm{OBC}\,\)\(\,\mathrm{A-OBC}\,\) ; ; ; ; ; ; ; ; ; ; ; ; ; 2020. , \(\,\mathrm{50}\,\) 2x^2+5x+3&=&x^2+6x+6\\ \(\,\mathrm{A,B}\,\)\(\,2\,\), \(\,\mathrm{OBC}\,\) &=&\color{red}{36^{\circ}}+\color{blue}{56^{\circ}}\\ \displaystyle =\frac{128}{40}\\ 2 \mathrm{DEC}&=&\mathrm{ECO+EOC}\\ 3731 1 . =x^2-10x+9\\ Benesse Corporation. \(\hspace{10pt}(\sqrt{10}+\sqrt{5})(\sqrt{6}-\sqrt{3})\\ \(\hspace{4pt}\color{magenta}{37}:\color{blue}{25}\), \(\displaystyle \underline{\frac{37}{25}}\), \(\,\mathrm{AE}\,\)\(\,\mathrm{AF}\,\) \(\begin{eqnarray} =\underline{11}\), (2) \mathrm{OH^2}&=&\mathrm{OA^2-AH^2}\\ , - 20201111; - 20201110; 12 - 2020119; . \(\begin{array}{|c|c|c|c|c|} \hline \(\,2\,\)\(\,\mathrm{36\,m}\,\) \(\hspace{10pt}3-4\times (-2)\\ =1.9\), (3) \(\,\mathrm{A}\,\)\(\,\mathrm{12km}\,\)\(\,\mathrm{C}\,\) & & & 5 \\ \hline \mathrm{AM}&=&\mathrm{BM}\\ \(\,\mathrm{A-B}\,\) Copyright Benesse Corporation. &=&6\sqrt{2} & & & 2 \\ \hline x-5&=&-3x+195\\ \(\,\mathrm{OBC}\,\) \(\,a^2:b^2\,\), \(\,\mathrm{ADF}\,\) , (3) \(\hspace{10pt}\mathrm{\color{red}{AB}=\color{red}{QR}}\) , \(\hspace{10pt}(\sqrt{10}+\sqrt{5})(\sqrt{6}-\sqrt{3})\\ \(\,\mathrm{BE:HA=2:8}\,\) \(\begin{eqnarray}\displaystyle \(\hspace{4pt}\displaystyle y=\frac{1}{5}\,x-1\), \(\,\mathrm{B}\,\)\(\,\mathrm{A}\,\)\(\,45\,\) \color{magenta}{18\sqrt{7}}&=&\frac{1}{3}\times \color{red}{18\sqrt{2}}\times \color{blue}{h}\\ \(\begin{eqnarray}\displaystyle \end{eqnarray}\), =\color{red}{\sqrt{15}}(\color{blue}{2-1})\\ &=&\color{red}{18\sqrt{2}} x&=&\frac{1\pm \sqrt{1+12}}{2}\\ PV \mathrm{DH:CB}&=&1:3\\ . \(\,20\,\), 2 =\underline{\sqrt{15}}\), \(\,\mathrm{OBC}\,\)\(\,S\,\)\(\,\mathrm{OI}\,\)

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